Question

Evaluate:

`4/(cot^2 30^0) +1/(sin^2 30^0) -2 cos^2 45^0 - sin^2 0^0`

Answer 1

On substituting the values of various T-ratios, we get:

`4/(cot^2 30^0) +1/(sin^2 30^0) -2 cos^2 45^0 - sin^2 0^0`

=`4/(sqrt(3))^2 + 1/(1/2)^2 -2xx(1/sqrt(2))^2-(0)^2`

=`4/3 +1/(1/4) -2xx1/2-0`

=`4/3 +4-1`

=`4/3+3=(4+9)/3=13/3`