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Evaluate : 4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5) - Mathematics

Sum

Evaluate : `4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`

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Solution

`4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`

= `4/(6^3)^(-2/3) + 1/(4^4)^(-3/4) + 2/(3^5)^(-1/5)`

= `4/(6)^-2 + 1/(4)^-3 + 2/(3)^-1`

= 4 x 62 + 1 x 43 + 2 x 3

= 4 x 36 + 1 x 64 + 6

= 144 + 64 + 6

= 214

Concept: Solving Exponential Equations
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APPEARS IN

Selina Concise Mathematics Class 9 ICSE
Chapter 7 Indices (Exponents)
Exercise 7 (C) | Q 16 | Page 101
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