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Evaluate : (2a−B) (2a+B) (4a2+B2) - Mathematics

Sum

Evaluate : (2a−b) (2a+b) (4a2+b2)

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Solution

(2a−b) (2a+b) (4a2+b2)

= [(2a)2−(b)2] (4a2+b2)

= (4a2−b2) (4a2+b2)

= (4a2)2 − (b2)2

= 16a4 − b4

Concept: Product of Sum and Difference of Two Terms
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APPEARS IN

Selina Concise Mathematics Class 8 ICSE
Chapter 12 Identities
Exercise 12 (A) | Q 3.3 | Page 150
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