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Evaluate : (-2/3)^-2^3 Xx (1/3)^-4 Xx 3^-1 Xx 1/6 - Mathematics

Sum

Evaluate : `[(-2/3)^-2]^3 xx (1/3)^-4 xx 3^-1 xx 1/6`

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Solution

`[(-2/3)^-2]^3 xx (1/3)^-4 xx 3^-1 xx 1/6`

= `[(- 3/2 )^2]^3 xx (3)^4 xx 1/3 xx 1/[ 3 xx 2 ]`

= `( -3/2)^6 xx (3)^2 xx 1/2`

= `3^(6 + 2 )/2^(6 + 1)`

= `3^8/2^7`

Concept: Solving Exponential Equations
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APPEARS IN

Selina Concise Mathematics Class 9 ICSE
Chapter 7 Indices (Exponents)
Exercise 7 (C) | Q 1.3 | Page 101
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