Question

Evaluate:

\[\int\sqrt{\frac{1 - \cos 2x}{2}}dx\]

Answer 1

\[\int\sqrt{\frac{1 - \cos 2x}{2}}dx\]
`=∫ \sqrt {{2 sin_2 x }/{2}} dx`   `[∴ 1 - cos 2x = 2 sin ^2 x]`
\[ = \int\text{sin x dx}\]
\[ = - \cos x + C\]