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Evaluate: ∫ √ 1 − Cos 2 X 2 D X - Mathematics

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Sum

Evaluate:

\[\int\sqrt{\frac{1 - \cos 2x}{2}}dx\]
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Solution

\[\int\sqrt{\frac{1 - \cos 2x}{2}}dx\]
`=∫ \sqrt {{2 sin_2 x }/{2}} dx`   `[∴ 1 - cos 2x = 2 sin ^2 x]`
\[ = \int\text{sin x dx}\]
\[ = - \cos x + C\]

Concept: Evaluation of Definite Integrals by Substitution
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APPEARS IN

RD Sharma Class 12 Maths
Chapter 19 Indefinite Integrals
Exercise 19.1 | Q 2.2 | Page 4

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