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Sum
Evaluate `int 1/((2"x" + 3))` dx
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Solution
Let I = `int 1/(2"x" + 3)` dx
∴ I = `(log |"2x" + 3|)/2` + c
Is there an error in this question or solution?
Evaluate `int 1/((2"x" + 3))` dx
Let I = `int 1/(2"x" + 3)` dx
∴ I = `(log |"2x" + 3|)/2` + c