Advertisement Remove all ads

Evaluate : ∫0π4cot2x⋅dx - Mathematics and Statistics

Advertisement Remove all ads
Advertisement Remove all ads
Sum

Evaluate : `int_0^(pi/4) cot^2x*dx`

Advertisement Remove all ads

Solution

`int_0^(pi/4) cot^2x*dx`

= `int_0^(pi/4) ("cosec"^2x - 1)*dx`

= `int_0^(pi/4) "cosec"^2x*dx - int_0^(pi/4)*dx`

= `[ - cot x]_0^(pi/4) - [x]_0^(pi/4)`

= `[( - cot pi/4) - ( - cot 0)] - [pi/4 - 0]`

= `- 1 + cot 0 - pi/4`.
The integral does not exist since cot 0 is not defined.

Concept: Fundamental Theorem of Integral Calculus
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×