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Find the Largest Number Which Exactly Divides 280 and 1245 Leaving Remainders 4 and 3, Respectively. - CBSE Class 10 - Mathematics

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Question

Find the largest number which exactly divides 280 and 1245 leaving remainders 4 and 3, respectively.

Solution

The required number when divides 280 and 1245 leaves the remainder 4 and 3, this means 280 4 – 216 and 1245 – 3 = 1245 – 3 = 1242 are completely divisible by the number

∴ The required number = HCF of 276 and 1242

By applying Euclid’s division lemma

1242 = 276 × 4 + 138

276 = 138 × 2 + 0

∴ HCF = 138

Hence the required numbers is 138.

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APPEARS IN

RD Sharma Solution for 10 Mathematics (2018 to Current)
Chapter 1: Real Numbers
Ex. 1.20 | Q: 12 | Page no. 28

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Solution Find the Largest Number Which Exactly Divides 280 and 1245 Leaving Remainders 4 and 3, Respectively. Concept: Euclid’s Division Lemma.
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