CBSE Class 10CBSE
Share
Notifications

View all notifications

Find the Hcf of the Following Pairs of Integers and Express It as a Linear Combination Of 506 and 1155. - CBSE Class 10 - Mathematics

Login
Create free account


      Forgot password?

Question

Find the HCF of the following pairs of integers and express it as a linear combination of 506 and 1155.

Solution

By applying Euclid’s division lemma

1155 = 506 × 2 + 143 …. (i)

Since remainder ≠ 0, apply division lemma on division 506 and remainder 143

506 = 143 × 3 + 77 ….(ii)

Since remainder ≠ 0, apply division lemma on division 143 and remainder 77

143 = 77 × 1 + 56 ….(iii)

Since remainder ≠ 0, apply division lemma on division 77 and remainder 66

77 = 66 × 1 + 11 …(iv)

Since remainder ≠ 0, apply division lemma on divisor 36 and remainder 9

66 = 11 × 6 + 0

∴ HCF = 11

Now, 11 = 77 – 6 × 11 [from (iv)]

= 77 – [143 – 77 × 1] × 1 [from (iii)]

= 77 – 143 × 1 – 77 × 1

= 77 × 2 – 143 × 1

= [506 – 143 × 3] × 2 – 143 × 1 [from (ii)]

= 506 × 2 – 143 × 6 – 143 × 1

= 506 × 2 – 143 × 7

= 506 × 2 – [1155 – 506 × 27 × 7] [from (i)]

= 506 × 2 – 1155 × 7 + 506 × 14

= 506 × 16 – 115 × 7

  Is there an error in this question or solution?

APPEARS IN

 RD Sharma Solution for 10 Mathematics (2018 to Current)
Chapter 1: Real Numbers
Ex. 1.20 | Q: 3.3 | Page no. 27

Video TutorialsVIEW ALL [1]

Solution Find the Hcf of the Following Pairs of Integers and Express It as a Linear Combination Of 506 and 1155. Concept: Euclid’s Division Lemma.
S
View in app×