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For the Following Equilibrium, Kc= 6.3 × 1014 at 1000 K Both the Forward and Reverse Reactions in the Equilibrium Are Elementary Bimolecular Reactions. What Is Kc, for the Reverse Reaction - CBSE (Science) Class 11 - Chemistry

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Question

For the following equilibrium, Kc= 6.3 × 1014 at 1000 K

NO (g) + O3 (g) ⇌NO2 (g) + O2 (g)

Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is Kc, for the reverse reaction?

Solution

It is given that `K_c` for the forward reaction is `6.3 xx 10^(14)`

Then, `K_c` for the reverse reaction will be,

`K'_C = 1/K_C`

`= 1/(6.3 xx 10^(14))`

`= 1.59 xx 10^(-15)`

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Solution For the Following Equilibrium, Kc= 6.3 × 1014 at 1000 K Both the Forward and Reverse Reactions in the Equilibrium Are Elementary Bimolecular Reactions. What Is Kc, for the Reverse Reaction Concept: Equilibrium in Chemical Processes - Dynamic Equilibrium.
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