HSC Science (General) 12th Board ExamMaharashtra State Board
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A Stone of Mass 5 kg. Tied to One End of a Rope of Length 0.8m, is Whirled in a Vertical Circle. Find the Minimum Velocity at the Highest Point and at the Midway Point. - HSC Science (General) 12th Board Exam - Physics

ConceptEquation for Velocity and Energy at Different Positions of Vertical Circular Motion

Question

A stone of mass 5 kg. tied to one end of a rope of length 0.8 m, is whirled in a vertical circle. Find the minimum velocity at the highest point and at the midway point.

[g = 9.8 m/s2]

Solution

m = 5 kg, r = 0.8 m, g = 9.8 m/s2
Minimum velocity at the highest point (vH) = ?
Minimum velocity at midway point (vM) = ?
At highest point,

V_H=sqrt(rg)

=sqrt(0.8xx9.8)

=sqrt7.84

=2.8 m/s

The minimum velocity at the highest point is 2.8 m/s. At midway point,

V_M=sqrt(3rg)

=sqrt(3)xx2.8

=1.732xx2.8

=4.849 m/s

~~4.85 m/s

Is there an error in this question or solution?

APPEARS IN

2013-2014 (October) (with solutions)
Question 2.5 | 2.00 marks

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Solution A Stone of Mass 5 kg. Tied to One End of a Rope of Length 0.8m, is Whirled in a Vertical Circle. Find the Minimum Velocity at the Highest Point and at the Midway Point. Concept: Equation for Velocity and Energy at Different Positions of Vertical Circular Motion.
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