# Solution - Equation of a Line in Space

Account
Register

Share

Books Shortlist

#### Question

The Cartesian equations of line are 3x -1 = 6y + 2 = 1 - z. Find the vector equation of line.

#### Solution

You need to to view the solution
Is there an error in this question or solution?

#### Similar questions

If the Cartesian equations of a line are  (3-x)/5=(y+4)/7=(2z-6)/4 , write the vector equation for the line.

view solution

Find the vector and Cartesian equations of the line through the point (1, 2, −4) and perpendicular to the two lines.

vecr=(8hati-19hatj+10hatk)+lambda(3hati-16hatj+7hatk) " and "vecr=(15hati+29hatj+5hatk)+mu(3hati+8hatj-5hatk)

view solution

Find the value of p, so that the lines l_1:(1-x)/3=(7y-14)/p=(z-3)/2 and l_2=(7-7x)/3p=(y-5)/1=(6-z)/5  are perpendicular to each other. Also find the equations of a line passing through a point (3, 2, – 4) and parallel to line l1.

view solution

Find k, if one of the lines given by 6x2 + kxy + y2 = 0 is 2x + y = 0

view solution

Find the Cartesian equation of the line which passes through the point (−2, 4, −5) and is parallel to the line 

view solution
S