Solution - Equation of a Line in Space



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A line passes through (2, −1, 3) and is perpendicular to the lines `vecr=(hati+hatj-hatk)+lambda(2hati-2hatj+hatk) and vecr=(2hati-hatj-3hatk)+mu(hati+2hatj+2hatk)` . Obtain its equation in vector and Cartesian from. 



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Reference Material

Solution for concept: Equation of a Line in Space. For the courses 12th CBSE (Arts), 12th CBSE (Commerce), 12th CBSE (Science)