# Solution - Equation of a Line in Space

Account
Register

Share

Books Shortlist

#### Question

Find the Cartesian equation of the line which passes through the point (−2, 4, −5) and is parallel to the line 

#### Solution

You need to to view the solution
Is there an error in this question or solution?

#### Similar questions VIEW ALL

Find the vector and cartesian equations of the line passing through the point (2, 1, 3) and perpendicular to the lines

(x-1)/1=(y-2)/2=(z-3)/3 and x/(-3)=y/2=z/5

view solution

A line passes through (2, −1, 3) and is perpendicular to the lines vecr=(hati+hatj-hatk)+lambda(2hati-2hatj+hatk) and vecr=(2hati-hatj-3hatk)+mu(hati+2hatj+2hatk) . Obtain its equation in vector and Cartesian from.

view solution

The Cartesian equations of line are 3x -1 = 6y + 2 = 1 - z. Find the vector equation of line.

view solution

Find the vector and Cartesian equations of the line through the point (1, 2, −4) and perpendicular to the two lines.

vecr=(8hati-19hatj+10hatk)+lambda(3hati-16hatj+7hatk) " and "vecr=(15hati+29hatj+5hatk)+mu(3hati+8hatj-5hatk)

view solution

The joint equation of the pair of lines passing through (2,3) and parallel to the coordinate axes is

1.  xy -3x - 2y + 6 = 0
2. xy +3x + 2y + 6 = 0
3. xy = 0
4. xy - 3x - 2y - 6 = 0
view solution

#### Reference Material

Solution for concept: Equation of a Line in Space. For the courses 12th CBSE (Arts), 12th CBSE (Commerce), 12th CBSE (Science), PUC Karnataka Science
S