Department of Pre-University Education, Karnataka course PUC Karnataka Science Class 12
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Two Capacitors of Capacitances 4⋅0 µF and 6⋅0 µF Are Connected in Series with a Battery of 20 V. Find the Energy Supplied by the Battery. - Physics

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Question

Two capacitors of capacitances 4⋅0 µF and 6⋅0 µF are connected in series with a battery of 20 V. Find the energy supplied by the battery.

Solution

Given : 

`C_1 = 4  "uF"`

`C_2 = 6  "uF"`

`V = 20 V`

Now,
The equivalent capacitance is given by 

`C_(eq) =( C_1C_2)/(C_1+C_2) = (4 xx 6)/(4+6) = 2.4  "uF"`

The energy supplied by the battery is given by 

`E = C_(eq) V^2`

= `(2.4  "uF") xx (20)^2`

= `(2.4  "uF") xx 400 = 960  "uJ"`

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Solution Two Capacitors of Capacitances 4⋅0 µF and 6⋅0 µF Are Connected in Series with a Battery of 20 V. Find the Energy Supplied by the Battery. Concept: Energy Stored in a Capacitor.
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