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# Solution - Explain What Would Happen If in the Capacitor Given in Exercise 2.8, a 3 Mm Thick Mica Sheet Were Inserted Between the Plates - CBSE (Science) Class 12 - Physics

ConceptEnergy Stored in a Capacitor

#### Question

Explain what would happen if in the capacitor given in Exercise 2.8, a 3 mm thick mica sheet (of dielectric constant = 6) were inserted between the plates,

(a) While the voltage supply remained connected.

(b) After the supply was disconnected.

#### Solution

(a) Dielectric constant of the mica sheet, k = 6

Initial capacitance, C = 1.771 × 10−11 F

New Capacitance, C''=kC=6xx1.771xx10^-11=106 pF

Supply voltage, = 100 V

New Capacitance, q'=C'V=6xx1.771xx10^-9=1.06 xx 10^-8pF

Potential across the plates remains 100 V.

(b) Dielectric constant, k = 6

Initial capacitance, C = 1.771 × 10−11 F

New Capacitance, C''=kC=6xx1.771xx10^-11=106 pF

If supply voltage is removed, then there will be no effect on the amount of charge in the plates.

Charge = 1.771 × 10−9 C

Potential across the plates is given by,

therefore V'=q/C'

=(1.771xx10^-9)/(106xx10^-12)

=16.7 V

Is there an error in this question or solution?

#### Reference Material

Solution for question: Explain What Would Happen If in the Capacitor Given in Exercise 2.8, a 3 Mm Thick Mica Sheet Were Inserted Between the Plates concept: Energy Stored in a Capacitor. For the courses CBSE (Science), CBSE (Arts), CBSE (Commerce)
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