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The Amplitude of the Magnetic Field Part of a Harmonic Electromagnetic Wave in Vacuum Is B0 = 510 nT. What is the Amplitude of the Electric Field Part of the Wave? - CBSE (Science) Class 12 - Physics

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Question

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electric field part of the wave?

Solution

Amplitude of magnetic field of an electromagnetic wave in a vacuum,

B0 = 510 nT = 510 × 10−9 T

Speed of light in a vacuum, c = 3 × 108 m/s

Amplitude of electric field of the electromagnetic wave is given by the relation,

E = cB0

= 3 × 10× 510 × 10−9 = 153 N/C

Therefore, the electric field part of the wave is 153 N/C.

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APPEARS IN

 NCERT Solution for Physics Textbook for Class 12 (2018 to Current)
Chapter 8: Electromagnetic Waves
Q: 7 | Page no. 286

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Solution The Amplitude of the Magnetic Field Part of a Harmonic Electromagnetic Wave in Vacuum Is B0 = 510 nT. What is the Amplitude of the Electric Field Part of the Wave? Concept: Electromagnetic Waves.
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