How would you determine the standard electrode potential of the system Mg2+ | Mg?
The standard electrode potential of Mg2+ | Mg can be measured with respect to the standard hydrogen electrode, represented by Pt(s), H2(g) (1 atm) | H+(aq)(1 M).
A cell, consisting of Mg | MgSO4 (aq 1 M) as the anode and the standard hydrogen electrode as the cathode, is set up.
`Mg|Mg^(2+)(aq, 1M) || H^(+)(aq,1M)|H_2(g, 1 "bar"), Pt_((x))`
Then, the emf of the cell is measured and this measured emf is the standard electrode potential of the magnesium electrode.
`E^(theta) = E_R^(theta)-E_L^(theta)`
Here `E_R^theta` or the standard hydrogen electrode is zero.
`:.E^(theta) = 0 - E_L^(theta)`
`= - E_L^(theta)`
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