Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12
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A Charge of 1 µC is Given to One Plate of a Parallel-plate Capacitor of Capacitance 0⋅1 µF and a Charge of 2 µC is Given to the Other Plate. Find the Potential Difference Developed Between the Plates. - Physics

ConceptElectric Potential Difference

Question

A charge of 1 µC is given to one plate of a parallel-plate capacitor of capacitance 0⋅1 µF and a charge of 2 µC is given to the other plate. Find the potential difference developed between the plates.

Solution

Charges on the plates :

q_1 = 1  "uC" = 1 xx 10^-6 C

q_2 = 2  "uC" = 2 xx 10^-6 C

The effective charge on the capacitor is given by q_"net" = (q_2 - q_1)/2 = ((2-1) xx 10^-6)/2 = 0.5 xx 10^-6  "C"

The potential difference is given by V = q_"net"/C = (0.5 xx 10^-6)/(0.1 xx 10^-6) = 5V

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Solution A Charge of 1 µC is Given to One Plate of a Parallel-plate Capacitor of Capacitance 0⋅1 µF and a Charge of 2 µC is Given to the Other Plate. Find the Potential Difference Developed Between the Plates. Concept: Electric Potential Difference.
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