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Solution - Millikan’S Oil Drop Experiment - Estimate the Radius of the Drop - Electric Field - Physical Significance of Electric Field

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Question

An oil drop of 12 excess electrons is held stationary under a constant electric field of 2.55 × 104 N C−1in Millikan’s oil drop experiment. The density of the oil is 1.26 g cm−3. Estimate the radius of the drop. (= 9.81 m s−2= 1.60 × 10−19 C).

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Two point charges qA = 3 μC and qB = −3 μC are located 20 cm apart in vacuum.

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