#### Question

The figure shows the field lines on a positive charge. Is the work done by the field in moving a small positive charge from Q to P positive or negative? Give reason.

#### Solution

Work done = *q*.(potential at Q − potential at P), where *q* is the small positive charge

The electric potential at a point distant *r* due to the field created by a positive charge Q is given by

\[V = \frac{1}{4 \pi\epsilon_0}\frac{q}{r}\]

\[ \because r_P < r_Q \]

\[ \Rightarrow V_P > V_Q\]

∴ Work done will be negative.

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Solution The Figure Shows the Field Lines on a Positive Charge. is the Work Done by the Field in Moving a Small Positive Charge from Q to P Positive Or Negative? Give Reason. Concept: Electric Field Lines.