Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12
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# The Electric Field in a Region is Given by - Physics

ConceptElectric Field Introduction of Electric Field

#### Question

The electric field in a region is given by

vec"E"= 3/5"E"_0 vec"i" + 4/5 "E"_0 vec "i"  "with" " E"_0 = 2.0 xx 10^3 "N""C"^-1.

Find the flux of this field through a rectangular surface of area 0⋅2 m2 parallel to the y-z plane.

#### Solution

Given:
Electric field strength vec"E" = 3/5 "E"_0 hat"i" + 4/5 "E"_0 $\stackrel\frown{j}$,

where E0 = 2.0  103 N/C

he plane of the rectangular surface is parallel to the y-z plane. The normal to the plane of the rectangular surface is along the x axis. Only 3/5 "E"_0$\stackrel\frown{i}$, passes perpendicular to the plane; so, only this component of the field will contribute to flux.
On the other hand, 4/5 "E"_0$\stackrel\frown{j}$  moves parallel to the surface.
Surface area of the rectangular surface, = 0⋅2 m2

Flux,

phi = vec"E" . vec"a" = "E" xx "a"

phi = (3/5 xx 2 xx 10^3) xx ( 2 xx 10^-1) "N""m"^2 //"C"

phi = 0.24 xx 10^3 "N""m"^2//"C"

phi = 240 "N""m"^2//"C"

Is there an error in this question or solution?

#### APPEARS IN

Solution The Electric Field in a Region is Given by Concept: Electric Field - Introduction of Electric Field.
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