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A System Has Two Charges qA = 2.5 × 10^−7 C And qB= −2.5 × 10^−7 C Located at Points A: (0, 0, − 15 Cm) and B: (0, 0, + 15 Cm), Respectively. What Are the Total Charge and Electric Dipole Moment of the System? - CBSE (Science) Class 12 - Physics

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Question

A system has two charges qA = 2.5 × 10−7 C and qB = −2.5 × 10−7 C located at points A: (0, 0, − 15 cm) and B: (0, 0, + 15 cm), respectively. What are the total charge and electric dipole moment of the system?

Solution

Both the charges can be located in a coordinate frame of reference as shown in the given figure.

At A, amount of charge, qA = 2.5 × 107C

At B, amount of charge, qB = −2.5 × 10−7 C

Total charge of the system,

q = qA + qB

= 2.5 × 107 C − 2.5 × 10−7 C

= 0

Distance between two charges at points A and B,

d = 15 + 15 = 30 cm = 0.3 m

Electric dipole moment of the system is given by,

p = qA × d = qB × d

= 2.5 × 10−7 × 0.3

= 7.5 × 10−8 C m along positive z-axis

Therefore, the electric dipole moment of the system is 7.5 × 10−8 C m along positive z−axis.

  Is there an error in this question or solution?

APPEARS IN

 NCERT Solution for Physics Textbook for Class 12 (2018 to Current)
Chapter 1: Electric Charge and Fields
Q: 9 | Page no. 46
Solution A System Has Two Charges qA = 2.5 × 10^−7 C And qB= −2.5 × 10^−7 C Located at Points A: (0, 0, − 15 Cm) and B: (0, 0, + 15 Cm), Respectively. What Are the Total Charge and Electric Dipole Moment of the System? Concept: Electric Dipole.
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