HSC Science (Electronics) 12th Board ExamMaharashtra State Board
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Solution for Two springs of force constants K1 and K2 (K1> K2) are stretched by same force. If W1 and W2 be the work done stretching the springs then - HSC Science (Electronics) 12th Board Exam - Physics

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Question

Two springs of force constants K1 and K2 (K1> K2) are stretched by same force. If W1 and W2 be the work done stretching the springs then......

(a) W1=W2

(b) W1<W2

(c) W1>W2

(d) W1=W2=0

Solution

W1<W2

F1 = K1x1 and F2 = K2x2

Force is same

∴ K1x1=K2x2

∴x1<x2  ........(K1>K2)

Work done, `W_1=1/2K_1x_1^2 and W_2=1/2K_2x_1^2`

∴W1<W2  .........(K1>K2 and x1<x2)

 
 
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Solution for question: Two springs of force constants K1 and K2 (K1> K2) are stretched by same force. If W1 and W2 be the work done stretching the springs then concept: Elastic Energy. For the courses HSC Science (Electronics), HSC Science (Computer Science), HSC Science (General)
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