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# Find the Wave Number of a Photon Having Energy of 2.072 Ev - Physics

#### Question

Find the wave number of a photon having energy of 2.072 eV

Given : Charge on electron = 1.6 x 10-19 C,

Velocity of light in air = 3 x 108 m/s,

Planck’s constant = 6.63 x 10-34 J-s.

#### Solution

E = hv

:.v=E/h

v=C/lambda

∴ Wave number

1/lambda=v/c

=E/(hc)

=(2.072xx1.6xx10^(-19))/(6.63xx10^(-34)xx3xx10^8

=1/lambda=1.667xx10^6m^(-1)

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