Solution - The Energy of Photon of Wavelength X is - Einstein’s Equation - Particle Nature of Light



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The energy of photon of wavelength X is_____ .

[h = Planck’s constant, c = speed of light in vacuum]







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The momentum of a photon of de Broglie wavelength 5000Å is _______.

[Planck’s constant = 6.63 x10-34 J.s.]

(A) 1.326 x10-28 kg-m/s

(B) 7.54 x10-28 kg-m/s

(C) 1.326 x10-27 kg-m/s

(D) 7.54 x10-27 kg-m/s

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less momentum?

Give reasons to justify your answer.

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When radiations of wavelength λ1 and λ2 are incident on certain photosensitive, such that E1 > E2 . Then Planck's constant 'h' is ......................... .

(C = Velocity of light).

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  2. `((E_1 - E_2)lambda_1C)/((lambda_1 - lambda_2)lambda_2)`
  3. `((E_1 - E_2)lambda_1lambda_2)/(C(lambda_2 - lambda_1))`
  4. `((lambda_1 - lambda_2)C)/((E_1 - E_2)lambda_1 * lambda_2)`
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Solution for question: The Energy of Photon of Wavelength X is concept: Einstein’s Equation - Particle Nature of Light. For the courses 12th HSC Science (Computer Science), 12th HSC Science (Electronics), 12th HSC Science (General)