HSC Science (Computer Science) 12th Board ExamMaharashtra State Board
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Determine the Maximum Kinetic Energy in Joule and in Ev of the Ejects Electron for the Metal Surface When It is Exposed to a Radiation of Wavelength 180 Nm. - HSC Science (Computer Science) 12th Board Exam - Physics

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Question

The photoelectric threshold wavelength of a metal is 230 nm. Determine the maximum kinetic energy in joule and in eV of the ejects electron for the metal surface when it is exposed to a radiation of wavelength 180 nm.

[Planck’s constant : h = 6.63 * 10-34 Js, Velocity of light : C = 3 * 108 m/s.]

Solution

λ0 = 230 nm = 230 × 10−9m,

λ = 180 nm = 180 × 10−9m,
h = 6.63 × 10−34 J s, c = 3 × 108
m/s, K.E. (in joule and eV) = ?
Now,

∴ The maximum kinetic energy of the ejected electron is 2.402 × 10−19 J.

∴ The maximum kinetic energy of the ejected electron is 1.5 eV.

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APPEARS IN

 2013-2014 (October) (with solutions)
Question 8.2 | 7.00 marks

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Solution Determine the Maximum Kinetic Energy in Joule and in Ev of the Ejects Electron for the Metal Surface When It is Exposed to a Radiation of Wavelength 180 Nm. Concept: Einstein’s Equation - Particle Nature of Light.
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