HSC Science (Computer Science) 12th Board ExamMaharashtra State Board
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Calculate the Maximum Kinetic Energy in Ev of Photoelectrons Emitted, When Ultraviolet Light of Wavelength 2600a Falls on It. - HSC Science (Computer Science) 12th Board Exam - Physics

ConceptEinstein’s Equation - Particle Nature of Light

Question

The threshold wavelength of silver is 3800Å. Calculate the maximum kinetic energy in eV of photoelectrons emitted, when ultraviolet light of wavelength 2600Å falls on it.

(Planck’s constant, h =6.63 x 1O-34J.s.,

Velocity of light in air, c = 3 x 108 m / s)

Solution

Wavelength of silver, λ1 = 3800 Aº

Wavelength of ultraviolet light, λ2 = 2600 Aº

H = 6.63 × 10-34 Js

Velocity of light in air, c = 3 × 108 m/s

To calculate kinetic energy, K.E. = hv − hvº

"K.E."="hc"[1/lambda-1/lambda_o]

"K.E."=19.89xx10^-19[1/2.6-1/3.8]

"K.E."=(2.416xx10^-19)/(1.6xx10^-19)

K.E. = 1.51 eV

Hence, the maximum kinetic energy emitted by the photoelectron is 1.51 eV.

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2014-2015 (March) (with solutions)
Question 7.4 | 3.00 marks

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Solution Calculate the Maximum Kinetic Energy in Ev of Photoelectrons Emitted, When Ultraviolet Light of Wavelength 2600a Falls on It. Concept: Einstein’s Equation - Particle Nature of Light.
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