Question
Each side of a rhombus is 10 cm. If one of its diagonals is 16 cm find the length of the other diagonal.
Solution
We have,
ABCD is a rhombus with side 10 cm and diagonal BD = 16 cm
We know that diagonals of a rhombus bisect each other at 90°
∴ BO = OD = 8 cm
In ΔAOB, by pythagoras theorem
AO2 + BO2 = AB2
⇒ AO2 + 82 = 102
⇒ AO2 = 100 − 64 = 36
⇒ AO = `sqrt36` = 6 cm [By above property]
Hence, AC = 6 + 6 = 12 cm
Is there an error in this question or solution?
Solution Each Side of a Rhombus is 10 Cm. If One of Its Diagonals is 16 Cm Find the Length of the Other Diagonal. Concept: Application of Pythagoras Theorem in Acute Angle and Obtuse Angle.
