# Each Edge of a Cube is Increased by 50%. Find the Percentage Increase in the Surface Area of the Cube. - Mathematics

Each edge of a cube is increased by 50%. Find the percentage increase in the surface area of the cube.

#### Solution

"Let d be the edge of the cube"

∴surface area of cube= 6xxa^2

i.e, S_1=6a^2

According to problem when edge increased by 50% then the new edge becomes

=a+50/100xxa

=3/2a

"New surface area becomes" =6xx(3/2a)^2

i.e.,=6xx9/4a^2

s_2=27/2a^2

∴Increased surface Area = 27/2a^2-6a^2

=15/2a^2

So, increase in surface area (15/2a^2)/6a^2

=15/12xx100

=125%

Concept: Surface Area of a Cuboid
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#### APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 18 Surface Areas and Volume of a Cuboid and Cube
Exercise 18.1 | Q 10 | Page 14

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