Question

 `dy/dx = log x`

Answer 1

 `dy/dx = log x`

∴ dy = log x dx

Integrating on both sides, we get

∫ 1 dy =∫  (log x × 1) dx

∴ `y = log x ( int1dx )  – int [ d/dx (logx) int  1dx] `

∴ `y = log x(x) – int (1/x xx x ) dx`

= x log x – ∫ 1dx

∴ y = x log x – x + c