#### Question

Draw a triangle ABC with BC = 6 cm, AB = 5 cm and ∠ABC = 60°. Then construct a triangle whose sides are `3/4` of the corresponding sides of the ∆ABC.

#### Solution

A ΔA'BC' whose sides are `3/4`of the corresponding sides of ΔABC can be drawn as follows:

**Step 1**

Draw a ΔABC with side BC = 6 cm, AB = 5 cm and ∠ABC = 60°

**Step 2**

Draw a ray BX making an acute angle with BC on the opposite side of vertex A.

**Step 3**

Locate 4 points (as 4 is greater in 3 and 4), B_{1}, B_{2}, B_{3}, B_{4}, on line segment BX.

**Step 4**

Join B_{4}C and draw a line through B_{3}, parallel to B_{4}C intersecting BC at C'

**Step 5**

Draw a line through C' parallel to AC intersecting AB at A'. ΔA'BC' is the required triangle.

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Solution Draw a Triangle Abc with Bc = 6 Cm, Ab = 5 Cm and ∠Abc = 60°. Then Construct a Triangle Whose Sides Are 34 of the Corresponding Sides of the ∆Abc. Concept: Constructions Examples and Solutions.