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Draw a Right Triangle in Which the Sides (Other than Hypotenuse) Are of Lengths 5 Cm and 4 Cm. Then Construct Another Triangle Whose Sides Are 5/3 Times the Corresponding Sides of the Given Triangle. - Mathematics

Draw a right triangle in which the sides (other than hypotenuse) are of lengths 5 cm and 4 cm. Then construct another triangle whose sides are 5/3th times the corresponding sides of the given triangle.

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Solution

Given that

Construct a right triangle of sides let AB = 5cm, AC = 4cm and ∠A = 90° and then a triangle similar to it whose sides are 5/3th of the corresponding sides of .

We follow the following steps to construct the given

Step of construction

Step: I- First of all we draw a line segment AB = 5cm.

Step: II- With as centre and draw an angle ∠A = 90°.

Step: III- With as centre and radius AC = 4cm.

Step: IV -Join BC to obtain ΔABC.

Step: V -Below AB, makes an acute angle ∠BAX = 60°.

Step: VI -Along AX, mark off five points A1, A2, A3, A4 and A5 such that AA1 = A1A2 = A2A3 = A3A4 = A4A5

Step: VII -Join A3B.

Step: VIII -Since we have to construct a triangle each of whose sides is 5/3th of the corresponding sides of ΔABC.

So, we draw a line A5B on AX from point A5 which is A5B' || A3B, and meeting AB at B’.

Step: IX -From B’ point draw B'C' || BC, and meeting AC at C’

Thus, ΔAB'C' is the required triangle, each of whose sides is 5/3th of the corresponding sides of ΔABC.

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APPEARS IN

RD Sharma Class 10 Maths
Chapter 9 Constructions
Exercise 9.2 | Q 7 | Page 9
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