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Draw the Graphs of the Following Equations: 2x − 3y + 6 = 0 2x + 3y − 18 = 0 Y − 2 = 0 Find the Vertices of the Triangle So Obtained. Also, Find the Area of the Triangle. - Mathematics

Draw the graphs of the following equations:

2x − 3y + 6 = 0
2x + 3y − 18 = 0
y − 2 = 0

Find the vertices of the triangle so obtained. Also, find the area of the triangle.

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Solution

The given equations are

2x − 3y + 6 = 0 ......(i)

2x + 3y − 18 = 0 ........(ii)

y − 2 = 0 ...........(iii)

The two points satisfying (i) can be listed in a table as

x -3 6
y 0 6

The two points satisfying (ii) can be listed in a table as,

x 0 9
y 6 0

The two points satisfying (iii) can be listed in a table as,

x -1 8
y 2 2

Now, graph of equations (i), (ii) and (iii) can be drawn as,

It is seen that the coordinates of the vertices of the obtained triangle are

A(3,4), B(0,2), C(6,2)

∴ Area of ΔABC = 1/2 x Base x height =  1/2 x 6 x 2 sq unit =  6 sq units

  Is there an error in this question or solution?
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APPEARS IN

RD Sharma Class 10 Maths
Chapter 3 Pair of Linear Equations in Two Variables
Exercise 3.2 | Q 30 | Page 30
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