Draw the following:
A rhombus whose diagonals are 5.2 cm and 6.4 cm long.
In a rhombus, diagonals bisect each other at 90º. Therefore, the given rhombus ABCD can be drawn as follows.
1) A rough sketch of this rhombus ABCD is as follows.
2) Draw a line segment AC of 5.2 cm and draw its perpendicular bisector. Let it intersect the line segment AC at point O.
3) Draw arcs of `"6.4 cm"/2` = 3.2 cm on both sides of this perpendicular bisector. Let the arcs intersect the perpendicular bisector at point B and D.
4) Join points B and D with points A and C.
ABCD is the required rhombus.
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