# Divide Y 4 − 3 Y 3 + 1 2 Y 2 B Y 3 Y - Mathematics

Sum

Divide $y^4 - 3 y^3 + \frac{1}{2} y^2 by 3y$

#### Solution

$\frac{y^4 - 3 y^3 + \frac{1}{2} y^2}{3y}$
$= \frac{y^4}{3y} - \frac{3 y^3}{3y} + \frac{\frac{1}{2} y^2}{3y}$
$= \frac{1}{3} y^{(4 - 1)} - y^{(3 - 1)} + \frac{1}{6} y^{(2 - 1)}$
$= \frac{1}{3} y^3 - y^2 + \frac{1}{6}y$

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#### APPEARS IN

RD Sharma Class 8 Maths
Chapter 8 Division of Algebraic Expressions
Exercise 8.3 | Q 2 | Page 6