Divide: 63a4b5c6 by −9a2b4c3 - Mathematics

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Sum

Divide: 63a4b5c6 by −9a2b4c3

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Solution

`(63"a"^4"b"^5"c"^6)/(-9"a"^2"b"^4"c"^3)=(63/(-9))("a"^4/"a"^2)("b"^5/"b"^4)("c"^6/"c"^3)`

= −7a4−2 . b5−4 . c6−3

= −7a2bc3

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Chapter 11: Algebraic Expressions - Exercise 11 (D) [Page 145]

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Selina Concise Mathematics Class 8 ICSE
Chapter 11 Algebraic Expressions
Exercise 11 (D) | Q 1.05 | Page 145
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