# Div » P Find the Acceleration Due to Gravity of the Moon at a Point 1000 Km Above the Moon'S Surface. the Mass of the Moon is 7.4 × 1022 Kg and Its Radius is 1740 Km. - Physics

Sum

Find the acceleration due to gravity of the moon at a point 1000 km above the moon's surface. The mass of the moon is 7.4 × 1022 kg and its radius is 1740 km.

#### Solution

The acceleration due to gravity at a point at height h from the surface of the moon is given by $g = \frac{GM}{r^2}$ ,

where M is the mass of the moon; r is the distance of point from the centre of the moon and G is universal gravitational constant.

$\therefore g = \frac{GM}{\left( R + h \right)^2}$

$\Rightarrow g = \frac{6 . 67 \times {10}^{- 11} \times 7 . 4 \times {10}^{22}}{\left( 1740 + 1000 \right)^2 \times {10}^6}$

$\Rightarrow g = \frac{6 . 67 \times 7 . 4 \times {10}^{11}}{\left( 1740 + {1000}^2\times {10}^6 \right)}$

$\Rightarrow g = \frac{6 . 67 \times 7 . 4 \times {10}^{11}}{2740 \times 2740 \times {10}^6}$

$\Rightarrow g = 0 . 65 m/ s^2$

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#### APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 11 Gravitation
Q 6 | Page 226