Discuss the shape of the following molecules using the VSEPR model: BeCl2, BCl3, SiCl4, AsF5, H2S, PH3 - Chemistry

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Long Answer

Discuss the shape of the following molecules using the VSEPR model:

BeCl2, BCl3, SiCl4, AsF5, H2S, PH3

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Solution

BeCl2:

The central atom has no lone pair and there are two bond pairs. i.e., BeCl2 is of the type AB2. Hence, it has a linear shape.

BCl3:

The central atom has no lone pair and there are three bond pairs. Hence, it is of the type AB3. Hence, it is trigonal planar.

SiCl4:

The central atom has no lone pair and there are four bond pairs. Hence, the shape of SiCl4 is tetrahedral being the AB4 type molecule.

AsF5:

The central atom has no lone pair and there are five bond pairs. Hence, AsF5 is of the type AB5. Therefore, the shape is trigonal bipyramidal.

H2S:

The central atom has one lone pair and there are two bond pairs. Hence, H2S is of the type AB2E. The shape is Bent.

PH3:

The central atom has one lone pair and there are three bond pairs. Hence, PH3 is of the AB3E type. Therefore, the shape is trigonal pyramidal.

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Chapter 4: Chemical Bonding and Molecular Structure - EXERCISES [Page 134]

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NCERT Chemistry Part 1 and 2 Class 11
Chapter 4 Chemical Bonding and Molecular Structure
EXERCISES | Q 4.7 | Page 134

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