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Sum

Differentiate the following w. r. t. x. : e^{x} log x

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#### Solution

Let y = e^{x} log x

Differentiating w.r.t. x, we get

`dy/dx = d/dx ("e"^xlog x)`

= `"e"^xd/dx(logx) + (logx) d/dx ("e"^x)`

=`"e"^x(1/x) + (logx)("e"^x)`

= `"e"^x(1/x+logx)`

Concept: Definition of Derivative and Differentiability

Is there an error in this question or solution?

Chapter 9: Differentiation - Exercise 9.1 [Page 120]