Answer 1

Let y =`2/7 x^(7/2) + 5/2 x^(2/5)`

Differentiating w.r.t. x, we get

`dy/dx = d/dx (2/7x^(7/2) + 5/2 x^(2/5))`

= `2/7d/dxx^(7/2) + 5/2 d/dxx^(2/5)`

= `2/7 xx7/2x^(7/2-1) + 5/2xx2/5 x^(2/5-1)`

= `x^(5/2) + x^((-3)/5)`