Answer 1

Let y =`x/log x`

Differentiating w.r.t. x, we get

`dy/dx=d/dx(x/logx)`

= `(logxd/dx(x) - xd/dx(logx))/(logx)^2`

=  `(logx(1) - x(1/x))/(logx)^2`

= `(logx-1)/(logx)^2`