Maharashtra State BoardHSC Commerce 11th
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Differentiate the following function w.r.t.x : x2+1x - Mathematics and Statistics

Sum

Differentiate the following function w.r.t.x : `(x^2 + 1)/x`

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Solution

Let y = `(x^2 + 1)/x`

Differentiating w.r.t. x, we get

`dy/dx= d/dx((x^2 + 1)/x)`

= `(xd/dx(x^2 + 1) - (x^2 + 1)d/dx(x))/x^2`

= `(x(2x + 0) - (x^2 + 1)(1))/x^2`

= `(2x^2 - x^2 - 1)/x^2`

`dy/dx=(x^2 - 1)/x^2`

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APPEARS IN

Balbharati Mathematics and Statistics 1 (Commerce) 11th Standard Maharashtra State Board
Chapter 9 Differentiation
Exercise 9.2 | Q I. (2) | Page 122
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