Maharashtra State BoardHSC Commerce 11th
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Differentiate the following function w.r.t.x. : 2xlogx - Mathematics and Statistics

Sum

Differentiate the following function w.r.t.x. : `2^x/logx`

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Solution

Let y = `2^x/logx`

Differentiating w.r.t. x, we get

`dy/dx=d/dx(2^x/logx)`

=` (logxd/dx(2^x) - 2^xd/dx(logx))/(logx)^2`

= `(logx(2^xlog2) - 2^x(1/x))/(logx)^2`

= `((2^xlogx*log2)(-1/x))/(logx)^2`

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APPEARS IN

Balbharati Mathematics and Statistics 1 (Commerce) 11th Standard Maharashtra State Board
Chapter 9 Differentiation
Exercise 9.2 | Q I. (6) | Page 122
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