HSC Science (General) 12th Board ExamMaharashtra State Board
Share

Books Shortlist

# The Maximum Velocity of a Particle Performing Linear S.H.M. is 0.16 m/s. If Its Maximum Acceleration is 0.64 m/s^2, Calculate Its Period. - HSC Science (General) 12th Board Exam - Physics

ConceptDifferential Equation of Linear S.H.M.

#### Question

The maximum velocity of a particle performing linear S.H.M. is 0.16 m/s. If its maximum acceleration is 0.64 m/s2, calculate its period.

#### Solution

vmax = 0.16 m/s, amax =0.64 m/s2

Period (T) = ?
vmax = Aω and amax = Aω2

a_max/v_max=omega=(2pi)/T

T=(2pixxv_max)/a_max

=(2xx3.14xx0.16)/0.64

= 1.571 s
Period of particle is 1.571 s

Is there an error in this question or solution?

#### APPEARS IN

2013-2014 (October) (with solutions)
Question 2.6 | 2.00 marks

#### Video TutorialsVIEW ALL [1]

Solution The Maximum Velocity of a Particle Performing Linear S.H.M. is 0.16 m/s. If Its Maximum Acceleration is 0.64 m/s^2, Calculate Its Period. Concept: Differential Equation of Linear S.H.M..
S