The Maximum Velocity of a Particle Performing Linear S.H.M. is 0.16 m/s. If Its Maximum Acceleration is 0.64 m/s^2, Calculate Its Period. - HSC Science (General) 12th Board Exam - Physics
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The maximum velocity of a particle performing linear S.H.M. is 0.16 m/s. If its maximum acceleration is 0.64 m/s2, calculate its period.
vmax = 0.16 m/s, amax =0.64 m/s2
Period (T) = ?
vmax = Aω and amax = Aω2
`= 1.571 s`
Period of particle is 1.571 s
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Solution The Maximum Velocity of a Particle Performing Linear S.H.M. is 0.16 m/s. If Its Maximum Acceleration is 0.64 m/s^2, Calculate Its Period. Concept: Differential Equation of Linear S.H.M..