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Diagram of the Adjacent Picture Frame Has Outer Dimensions = 24 Cm × 28 Cm and Inner Dimensions 16 Cm × 20 Cm. Find the Area of Each Section of the Frame, If the Width of Each Section is Same. - Mathematics

Diagram of the adjacent picture frame has outer dimensions = 24 cm × 28 cm and inner dimensions 16 cm × 20 cm. Find the area of each section of the frame, if the width of each section is same.

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Solution

Given that, the width of each section is same. Therefore,

IB = BJ = CK = CL = DM = DN = AO = AP

IL = IB + BC + CL

28 = IB + 20 + CL

IB + CL = 28 cm − 20 cm = 8 cm

IB = CL = 4 cm

Hence, IB = BJ = CK = CL = DM = DN = AO = AP = 4 cm

Area of section BEFC = Area of section DGHA

=`[1/2 (20 + 28)(4)] cm^2 = 96 cm^2`

Area of section ABEH = Area of section CDGF

⇒Area of section ABEH = Area of section CDGF

= 1216+244=80 cm2

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APPEARS IN

NCERT Class 8 Maths Textbook
Chapter 11 Mensuration
Exercise 11.2 | Q 11 | Page 178
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