Diagonal AC and BD of trapezium ABCD, in which AB || DC, intersect each other at O. The triangle which is equal in area of ΔAOD is
Given: (1) ABCD is a trapezium, with parallel sides AB and DC
(2) Diagonals AC and BD intersect at O
To find: Area of ΔAOD equals to ?
Calculation: We know that ,” two triangles with the same base and between the same parallels are equal in area.”
Area of ΔADB = Area of ΔACB
Area of ΔAOB + Area of ΔAOD = Area of ΔAOB + Area of ΔBOC
Area of ΔAOD = Area of ΔBOC