Tamil Nadu Board of Secondary EducationHSC Science Class 11

# Determine whether the following function is differentiable at the indicated values. f(x) = |x2 – 1| at x = 1 - Mathematics

Sum

Determine whether the following function is differentiable at the indicated values.

f(x) = |x2 – 1| at x = 1

#### Solution

f(x) = {{:(-(x^2 - 1),  "if"  x < 1),(x^2 - 1,  "if"  x> 1):}

To find the left limit of f(x) at x = 1

When x → 1^-

f(x) = -(x^2 - 1)

f"'"(1^-)  =  lim_(x -> 1^-) (f(x) - f(1))/(x - 1)

= lim_(x -> 1^-) (-(x^2 - 1) - [-(1^2 - 1)])/(x - 1)

= lim_(x - 1^-) (-(x^2 - 1) - 0)/(x - 1)

= lim_(x -> 1^-) (-(x - 1)(x + 1))/(x - 1)

= lim_(x -> 1^-) - (x + 1)

f"'"(1^-) = -(1 + 1) = – 2  ........(1)

To find the right limit of f(x) at x = 1

When x → 1^+

f(x) = (x^2 - 1)

f"'"(1^+)  =  lim_(x -> 1^+) (f(x) - f(1))/(x - 1)

= lim_(x -> 1^+) ((x^2 - 1) - (1^2 - 1))/(x - 1)

= lim_(x - 1^+) ((x^2 - 1) - 0)/(x - 1)

= lim_(x -> 1^+) ((x - 1)(x + 1))/(x - 1)

= lim_(x -> 1^+) (x + 1)

f"'"(1^+) = (1 + 1) = 2  ........(2)

From equatios (1) and (2) we have

f"'"(1^+)  ≠  f"'"(1^+)

∴ f(x) is not differentiable at x = 1.

Concept: Differentiability and Continuity
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Chapter 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.1 [Page 147]

#### APPEARS IN

Tamil Nadu Board Samacheer Kalvi Class 11th Mathematics Volume 1 and 2 Answers Guide
Chapter 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.1 | Q 3. (ii) | Page 147
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