Determine the value of R for maximum power transfer and find the value of maximum transfer.
Solution
(1) Calculation of πππ»
Removing the variable resistor R from the network
Mesh 1 and 2 will form A loop.
Writing current equation for the loop.
πΌ2−πΌ1=4 ………………..(1)
Applying KVL to the loop,
8−πΌ1−5πΌ1−5πΌ2−10=0
−6πΌ1−5πΌ2=2 ………..(2)
From (1) and (2) we get,
πΌ1=−2π΄ and πΌ2=2π΄
Writing πππ» equation,
8−πΌ1−πππ»=0 => 8+2−πππ»=0
πππ=πππ
(2) Calculation of π
ππ»
Replacing the voltage source by short circuits and current sources by an open circuit
π
ππ» = 10Ω || 1Ω = 0.91Ω
For maximum power transfer
(3) Calculation of ππππ₯
`P_(max)=(V_(TH)^2)/(4R_(TH))=10^2/(4xx0.91)=27.47w`