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Determine the values of all the four quantum numbers of the 8^{th} electron in the O-atom and 15^{th} electron in Cl atom.

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#### Solution

(1) O (Z = 8) 1s^{2} 2s^{2} 2p_{x}^{2 }2p_{y}^{1} 2p_{z}^{1}

Four quantum numbers for 2p_{x}^{1} electron in oxygen atom:

n = principal quantum number = 2

l = azimuthal quantum number = 1

m = magnetic quantum number = +1

s = spin quantum number = `+1/2`

(2) Cl (Z = 17) 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p_{x}^{2} 3p_{y}^{2} 3p_{z}^{1}

Four quantum numbers for 15^{th} electron in chlorine atom:

n = 3, l = 1, m = 0, s = `+1/2`

(3) Cr (Z = 24) 1s^{2} 2s^{2} 2p^{2} 3s^{2} 3p^{2} 3d^{2} 4s^{1}

n = 3, l = 2, m = +2, s = `+1/2`

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